Question

This question has multiple correct options

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Correct option is

Slope , $m=tanθ=hc/e$ (compare above equation with $y=mx−c$)

If $V=0⇒hcϕ =λ1 $

Now from given graph,

for metal 1 : $hcϕ_{1} =0.001$

for metal 2: $hcϕ_{2} =0.002$

for metal 3: $hcϕ_{3} =0.004$

Thus, $ϕ_{1}:ϕ_{2}:ϕ_{3}=1:2:4$

Also, $ϕ=λ_{0}hc $ where $λ_{0}$ be the threshold wavelength.

For metal 2 : $λ_{02}=1/0.002=500nm$

For metal 3 : $λ_{02}=1/0.004=250nm$

As the wavelength of violet colour is around 400 nm so only metal 2 can eject violet colour light but not metal 3.

Thus, options A and C is right.

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